M+F=R(e) with this 3 natural basic Laws equation you can explain the micro and the macro. Without this, you still do not know and Bob is getting there 👍👌
Dear Bob. Just watched your pyramid one and recapped with your suggestion. The understanding and revelation, to me, of what you are sharing l must thank you for. Have you thought about making a moving image of the FTM. In slow motion?
There's a numerical summation series related to an offshoot of the golden ratio I read in an Egyptology book on the Great Pyramids which says that if you start with the numbers 5 and 6 and sum them together in a manner equivalent to the Fibonacci algorithm, then at position #13 (if 5 is at position #1), then the subtotal of 1309 will result.
5 + 6 = 11
6 + 11 = 17
11 + 17 = 28
17 + 28 = 45 (1/8 of 360°)
28 + 45 = 73
45 + 73 = 118
73 + 118 = 191
118 + 191 = 309 (1/2 of 618)
191 + 309 = 500
309 + 500 = 809 (1/2 of 1618)
500 + 809 = 1309 (1/2 of 2618)
1308.99693899574718 = 2 × π × 10,000 ÷ 48
And if you divide this by 10k, then you get the 48th slice of 2π in radians good to four decimal places.
0.1309 × 48 = 2π
Interesting multiples also occur at position #6 (1/8 divisions of a circle in 360 degrees), and at #10 and #12 and #13 at the second multiple (rather than the 48th) yielding 618, 1618, and 2618 respectively.
M+F=R(e) with this 3 natural basic Laws equation you can explain the micro and the macro. Without this, you still do not know and Bob is getting there 👍👌
Dear Bob. Just watched your pyramid one and recapped with your suggestion. The understanding and revelation, to me, of what you are sharing l must thank you for. Have you thought about making a moving image of the FTM. In slow motion?
Suppppp tammy…. Your cool missssies I cannnie get onto my private messssages anyway🫣…. But that’s another thing that … lol,hope everyone is well…. ….
There's a numerical summation series related to an offshoot of the golden ratio I read in an Egyptology book on the Great Pyramids which says that if you start with the numbers 5 and 6 and sum them together in a manner equivalent to the Fibonacci algorithm, then at position #13 (if 5 is at position #1), then the subtotal of 1309 will result.
5 + 6 = 11
6 + 11 = 17
11 + 17 = 28
17 + 28 = 45 (1/8 of 360°)
28 + 45 = 73
45 + 73 = 118
73 + 118 = 191
118 + 191 = 309 (1/2 of 618)
191 + 309 = 500
309 + 500 = 809 (1/2 of 1618)
500 + 809 = 1309 (1/2 of 2618)
1308.99693899574718 = 2 × π × 10,000 ÷ 48
And if you divide this by 10k, then you get the 48th slice of 2π in radians good to four decimal places.
0.1309 × 48 = 2π
Interesting multiples also occur at position #6 (1/8 divisions of a circle in 360 degrees), and at #10 and #12 and #13 at the second multiple (rather than the 48th) yielding 618, 1618, and 2618 respectively.